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Select the correct statement.

1. Carbon-carbon bond order in graphite is more than diamond
2. Carbon-carbon bond order in graphite is less than diamond
3. Hybridization of each carbon in diamonds is \( S p_{3} \)
4. Hybridization of each carbon in graphite is \( S p_{3} \)

Correct answer: Hybridization of each carbon in diamonds is \( S p_{3} \)

Solution

In diamond, each carbon forms four single bonds in a tetrahedral arrangement, which corresponds to sp3 hybridization. Graphite instead has sp2-hybridized carbons arranged in planar sheets with delocalized pi electrons.

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