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Propan-1-ol may be prepared by the reaction of propene with

1. H3BO3
2. H2SO4/H2O
3. B2H6/NaOH/H2O2
4. CH3C-O-H

Correct answer: B2H6/NaOH/H2O2

Solution

Propan-1-ol is prepared by the hydroboration-oxidation of propene using B2H6 followed by treatment with NaOH and H2O2, which adds -OH to the less substituted carbon (anti-Markovnikov addition).

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