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The rates of reaction of different alcohols with Lucas reagent follows the order: 3° alcohol > 2° alcohol > 1° alcohol.

1. Since carbocations are formed as intermediate, more stable the carbocation, higher will be the reactivity of the parent compound (alcohol).
2. 2-methylpropan-2-ol generates a 3° carbocation, so it will react fastest; other three generate either 1° or 2° carbocations.
3. CH3CH2OH reacts slower than CH3CH(OH)CH3.
4. CH3CH2OH reacts faster than CH3CH(OH)CH3.

Correct answer: Since carbocations are formed as intermediate, more stable the carbocation, higher will be the reactivity of the parent compound (alcohol).

Solution

The reactivity order with Lucas reagent is determined by the stability of the carbocation intermediate. Tertiary carbocations are the most stable, followed by secondary, and then primary, which explains the given order.

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