Exams › NEET › Chemistry

For a first order reaction A → B, given a = 0.8 mol, calculate (a − x) when x = 0.6.

1. (a − x) = 0.8 − 0.6 = 0.2
2. (a − x) = 0.8 − 0.6 = 0.4
3. (a − x) = 0.8 − 0.6 = 0.6
4. (a − x) = 0.8 − 0.6 = 0.8

Correct answer: (a − x) = 0.8 − 0.6 = 0.2

Solution

The formula for (a − x) is straightforward subtraction: initial concentration (a) minus the reacted amount (x). Substituting a = 0.8 and x = 0.6 gives (a − x) = 0.8 − 0.6 = 0.2.

Related NEET Chemistry questions

• Why is catalyst added while preparing oxygen from decomposition of \( K C l O_{3} ? \)
• In the Arrhenius equation \( k=A e^{E / R T} \) rate will be constant at:
• As the concentration of reactants increases:
• Assertion The rate of reaction can also increase w.r.t its product if one of the product act as catalyst. Reason A catalyst lowers the activation energy of reactions. Read the above assertion and reason and choose the correct option regarding ¡t.
• Assertion Chlorine reacts more rapidly with \( \boldsymbol{H}_{2}, \) in comparision to \( \boldsymbol{O}_{\mathbf{2}} \) Reason \( D-C l \) bond is stronger in comparison to \( H-C l \) bond
• In the Haber process for the industrial manufacturing of ammonia involving the reaction \( N_{2}(g)+3 H_{2}(g) \rightleftharpoons 2 N H_{3}(g) \) at 200atm pressure in the presence of a catalyst, a temperature of about \( 500^{\circ} \mathrm{C} \) is used. This is considered as optimum temperature for the process because:

⚔️ Practice NEET Chemistry free + battle 1v1 →