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3A → 2B Rate of appearance of B is equal to rate of disappearance of A. 1/2 d[B]/dt = -1/3 d[A]/dt

1. Rate of appearance of B is equal to rate of disappearance of A.
2. 1/2 d[B]/dt = -1/3 d[A]/dt
3. d[B]/dt = 2/3 d[A]/dt
4. Rate of reaction is proportional to A.

Correct answer: d[B]/dt = 2/3 d[A]/dt

Solution

The stoichiometric relationship between A and B in the reaction 3A → 2B implies that the rate of appearance of B is related to the rate of disappearance of A by the ratio of their coefficients. Thus, d[B]/dt = (2/3)(-d[A]/dt).

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