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Activation energy (Ea) and rate constants (k₁ and k₂) of a chemical reaction at two different temperatures (T₁ and T₂) are related by:

1. ln k₂/k₁ = -Ea/R (1/T₁ - 1/T₂)
2. ln k₂/k₁ = -Ea/R (1/T₂ - 1/T₁)
3. ln k₂/k₁ = Ea/R (1/T₂ - 1/T₁)
4. ln k₂/k₁ = Ea/R (1/T₁ - 1/T₂)

Correct answer: ln k₂/k₁ = -Ea/R (1/T₂ - 1/T₁)

Solution

The Arrhenius equation relates the rate constants at two temperatures as ln(k₂/k₁) = -Ea/R (1/T₂ - 1/T₁). Rearranging the terms gives the correct form: ln(k₂/k₁) = -Ea/R (1/T₁ - 1/T₂).

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