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A substance 'A' decomposes by a first order reaction starting initially with [A] = 2.00 m and after 200 min, [A] becomes 0.15 m. For this reaction t₁/₂ is
- 53.72 min
- 50.49 min
- 48.45 min
- 46.45 min
Correct answer: 50.49 min
Solution
For a first-order reaction, the integrated rate law is ln([A]₀/[A]) = kt. Using the given data, k can be calculated, and then t₁/₂ = 0.693/k. Substituting values gives t₁/₂ ≈ 50.49 min.
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