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The rate of a first order reaction is 1.5 × 10⁻² mol L⁻¹ min⁻¹ at 0.5 M concentration of the reactant. The half-life of the reaction is
- 0.383 min
- 23.1 min
- 6.73 min
- 1.53 min
Correct answer: 6.73 min
Solution
For a first-order reaction, rate = k[A]. Here, k = rate/[A] = (1.5 × 10⁻²)/(0.5) = 3 × 10⁻² min⁻¹. The half-life (t₁/₂) for a first-order reaction is 0.693/k. Substituting k = 3 × 10⁻², t₁/₂ = 0.693/(3 × 10⁻²) = 23.1 min.
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