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In a zero-order reaction for every 10°C rise of temperature, the rate is doubled. If the temperature is increased from 100°C to 1000°C, the rate of the reaction will become:
- 256 times
- 512 times
- 64 times
- 128 times
Correct answer: 512 times
Solution
For every 10°C rise, the rate doubles. From 100°C to 1000°C, the temperature increases by 900°C, which corresponds to 90 intervals of 10°C. The rate becomes 2^9 = 512 times.
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