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For a reaction between A and B the order with respect to A is 2 and the order with respect to B is 3. The concentrations of both A and B are doubled, the rate will increase by a factor of:

1. 10
2. 12
3. 16
4. 32

Correct answer: 32

Solution

The rate of reaction is proportional to [A]^2[B]^3. Doubling [A] increases the rate by 2^2 = 4, and doubling [B] increases the rate by 2^3 = 8. The total increase is 4 × 8 = 32.

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