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The rate of a first-order reaction is 0.04 mol l⁻¹s⁻¹ at 10 seconds and 0.03 mol l⁻¹s⁻¹ at 20 seconds after initiation of the reaction. The half-life period of the reaction is
- 24.1 s
- 34.1 s
- 44.1 s
- 54.1 s
Correct answer: 24.1 s
Solution
For a first-order reaction, the rate constant k can be calculated using the formula k = (1/t) * ln([R]₀/[R]). Using the given rates at two different times, the half-life (t₁/₂) is determined using t₁/₂ = 0.693/k. Substituting the values gives t₁/₂ ≈ 24.1 s.
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