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Consider the reaction N₂(g) + 3H₂(g) → 2NH₃(g)
The equality relationship between d[NH₃]/dt and -d[H₂]/dt is
- d[NH₃]/dt = -d[H₂]/dt
- d[NH₃]/dt = -1/3 d[H₂]/dt
- d[NH₃]/dt = -3 d[H₂]/dt
- d[NH₃]/dt = -2/3 d[H₂]/dt
Correct answer: d[NH₃]/dt = -1/3 d[H₂]/dt
Solution
The stoichiometric coefficients in the reaction indicate that 3 moles of H₂ are consumed for every 2 moles of NH₃ formed. Thus, the rate of formation of NH₃ is one-third the rate of consumption of H₂, with opposite signs due to consumption.
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