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The equilibrium constant of the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) ; E° = 0.46 V at 298 K is

1. 2.0 × 10^10
2. 4.0 × 10^10
3. 4.0 × 10^15
4. 2.4 × 10^10

Correct answer: 4.0 × 10^10

Solution

The equilibrium constant (K) can be calculated using the Nernst equation: ΔG° = -nFE° and ΔG° = -RTlnK. Substituting values (n=2, F=96500 C/mol, R=8.314 J/mol·K, T=298 K, E°=0.46 V), we find K ≈ 4.0 × 10^10.

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