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Relative lowering of vapour pressure depends upon the mole fraction of solute. i.e., p° - p / p° = mole fraction of solute.

1. Relative lowering of vapour pressure depends upon the mole fraction of solute.
2. p° - p / p° = mole fraction of solute
3. Mole fraction of solute = 0.4
4. Depression of 2 × 0.2 mm Hg vapour pressure requires 2 × 0.2 mole fraction of solute.

Correct answer: Relative lowering of vapour pressure depends upon the mole fraction of solute.

Solution

The statement in option A correctly describes the principle of relative lowering of vapour pressure, which is directly proportional to the mole fraction of the solute in the solution.

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