Exams › NEET › Chemistry

A solution contains non-volatile solute of molecular mass M₂. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure?

1. M₂ = (m₂/V)RT
2. M₂ = (m₂/V)RT
3. M₂ = (m₂/V)RT
4. M₂ = (m₂/V)πRT

Correct answer: M₂ = (m₂/V)RT

Solution

The molecular mass of the solute can be calculated using the formula derived from the osmotic pressure equation: π = (n₂/V)RT, where n₂ = m₂/M₂. Rearranging gives M₂ = (m₂/V)RT/π.

Related NEET Chemistry questions

• At \( 80^{\circ} \mathrm{C}, \) the vapour pressure of pure liquid \( A \) is 520 mmHg and that of pure liquid \( B \) is 1000 mmHg. If a mixture solution of \( A \) and \( B \) boils at \( 80^{\circ} \) and 1 atm pressure, the amount of \( A \) (mole percent) in the mixture is:
• A solution is prepared by adding 2 g of substance \( A \) to 18 g of water. The mass percent of the solute is:
• Which of the following solutions shows positive deviation from Raoult's law?
• Which of the following forms an ideal solution? This question has multiple correct options
• Which of the following will show a negative deviation from Raoult's law?
• An aqueous solution of methanol in water has vapour pressure:

⚔️ Practice NEET Chemistry free + battle 1v1 →