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A 0.0020 m aqueous solution of an ionic compound Co(NH₃)₅(NO₂)Cl freezes at −0.00732°C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (Kf = 1.86°C/m).

1. 3
2. 4
3. 1
4. 2

Correct answer: 4

Solution

The freezing point depression is given by ΔTf = i × Kf × m. Substituting the values, −0.00732 = i × 1.86 × 0.0020. Solving for i gives i = 2. The compound Co(NH₃)₅(NO₂)Cl dissociates into 4 ions: [Co(NH₃)₅(NO₂)]²⁺ and 2Cl⁻. Thus, the correct answer is 4.

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