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A solution of sucrose (molar mass = 342 g mol⁻¹) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water = 1.86 K kg mol⁻¹).

1. 0.372°C
2. 0.520°C
3. 0.372°C
4. 0.570°C

Correct answer: 0.372°C

Solution

The molality of the solution is calculated as moles of solute (68.5 g / 342 g mol⁻¹) divided by mass of solvent in kg (1 kg). Using ΔTf = Kf × molality, the freezing point depression is 0.372 K. Subtracting this from 0°C gives -0.372°C.

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