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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be
- 101 °C
- 100 °C
- 102 °C
- 103 °C
Correct answer: 101 °C
Solution
The boiling point elevation is calculated using ΔTb = Kb × m, where m is the molality. The given data suggests a small elevation, and the closest option is 101 °C.
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