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Lithium metal crystallises in a body centred cubic crystal. If the length of the side of the unit cell of lithium is 351 pm, the atomic radius of lithium will be:

1. 151.8 pm
2. 75.5 pm
3. 300.5 pm
4. 240.8 pm

Correct answer: 151.8 pm

Solution

In a body-centred cubic (BCC) lattice, the relation between the edge length (a) and the atomic radius (r) is given by: \( \sqrt{3}a = 4r \). Substituting \( a = 351 \) pm, we get \( r = \frac{\sqrt{3} \times 351}{4} \approx 151.8 \) pm.

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