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AB crystallizes in a body centered cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is:

1. 335 pm
2. 250 pm
3. 200 pm
4. 300 pm

Correct answer: 335 pm

Solution

In a body-centered cubic lattice, the distance between two oppositely charged ions is half the body diagonal. The body diagonal is √3a, so the distance is (√3a)/2. Substituting a = 387 pm, the distance is (√3 × 387)/2 = 335 pm.

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