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A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y⁻) will be:

1. 275.1 pm
2. 322.5 pm
3. 241.5 pm
4. 165.7 pm

Correct answer: 241.5 pm

Solution

In the NaCl structure, the radius ratio (r+/r−) for cation to anion is approximately 0.414 for stable coordination. Given the cation radius is 100 pm, the anion radius can be calculated as r− = r+/0.414 = 100/0.414 ≈ 241.5 pm.

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