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HC≡CH + NaNH2 → HC≡CNa

1. HC≡CH2–Br → HC≡CH2–CH3
2. HC≡CH2–C≡C–CH3
3. HC≡CH2–C≡C–CH3
4. HC≡CH2–C≡C–CH3

Correct answer: HC≡CH2–Br → HC≡CH2–CH3

Solution

The reaction involves the deprotonation of acetylene (HC≡CH) by sodium amide (NaNH2), forming the acetylide ion (HC≡CNa). This ion can further react with alkyl halides to form longer carbon chains.

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