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In the hydrocarbon CH3—CH=CH—CH2—C≡CH, the state of hybridization of carbons 1, 3 and 5 are in the following sequence:

1. sp2, sp3, sp3
2. sp, sp3, sp2
3. sp2, sp2, sp3
4. sp3, sp2, sp

Correct answer: sp3, sp2, sp

Solution

Carbon 1 (CH3) is sp3 hybridized as it forms four sigma bonds. Carbon 3 (CH=) is sp2 hybridized due to one double bond and two sigma bonds. Carbon 5 (C≡) is sp hybridized because it forms one triple bond and one sigma bond.

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