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When CH3Cl and AlCl3 are used in Friedel-Crafts reaction, the electrophile is

1. Cl+
2. AlCl4−
3. CH3+
4. AlCl3+

Correct answer: CH3+

Solution

In the Friedel-Crafts reaction, CH3Cl reacts with AlCl3 to generate the electrophile CH3+ (methyl carbocation) through the polarization of the C-Cl bond by AlCl3.

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