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Which is the most suitable reagent among the following to distinguish compound (3) from rest of the compounds?
1. CH3−C≡C−CH3
2. CH3−CH2−CH2−CH3
3. CH3−CH2C≡CH
4. CH3−CH=CH2
- Bromine in carbon tetrachloride
- Bromine in acetic acid
- Alk. KMnO4
- Ammoniacal silver nitrate
Correct answer: Ammoniacal silver nitrate
Solution
Compound (3) contains a terminal alkyne (-C≡CH group), which reacts with ammoniacal silver nitrate to form a white precipitate of silver acetylide. The other compounds do not have a terminal alkyne and will not react similarly.
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