A hydrocarbon ‘A’ on chlorination gives ‘B’ which on heating with alcoholic potassium hydroxide changes into another hydrocarbon ‘C’. The latter decolourises Baeyer’s reagent and on ozonolysis forms formaldehyde. ‘A’ is:

Question

Accepted Answer

Ethane. The hydrocarbon 'A' is ethane. On chlorination, it forms ethyl chloride ('B'), which on heating with alcoholic KOH undergoes dehydrohalogenation to form ethene ('C'). Ethene decolourises Baeyer's reagent and produces formaldehyde on ozonolysis, confirming the identity of 'A' as ethane.

A hydrocarbon ‘A’ on chlorination gives ‘B’ which on heating with alcoholic potassium hydroxide changes into another hydrocarbon ‘C’. The latter decolourises Baeyer’s reagent and on ozonolysis forms formaldehyde. ‘A’ is:

Solution

Related NEET Chemistry questions