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The stability of carbanions in the following :
(a) RC≡C⁻
(b)
(c) R₂C=CH⁻
(d) R₃C−CH₂⁻
is in the order of :
- (a) (a) > (b) > (c) > (d)
- (b) (b) > (c) > (d) > (a)
- (c) (d) > (b) > (c) > (a)
- (d) (a) > (c) > (b) > (d)
Correct answer: (a) (a) > (b) > (c) > (d)
Solution
The stability of carbanions depends on the extent of s-character in the hybrid orbital holding the negative charge. Higher s-character leads to greater stability due to increased electronegativity. Thus, the order is sp (RC≡C⁻) > sp² (R₂C=CH⁻) > sp³ (R₃C−CH₂⁻).
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