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The stability of carbanions in the following : (a) RC≡C⁻ (b) (c) R₂C=CH⁻ (d) R₃C−CH₂⁻ is in the order of :

  1. (a) (a) > (b) > (c) > (d)
  2. (b) (b) > (c) > (d) > (a)
  3. (c) (d) > (b) > (c) > (a)
  4. (d) (a) > (c) > (b) > (d)

Correct answer: (a) (a) > (b) > (c) > (d)

Solution

The stability of carbanions depends on the extent of s-character in the hybrid orbital holding the negative charge. Higher s-character leads to greater stability due to increased electronegativity. Thus, the order is sp (RC≡C⁻) > sp² (R₂C=CH⁻) > sp³ (R₃C−CH₂⁻).

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