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Arrange the following in increasing order of stability:

1. (CH3)2C−CH2CH3 (B) (CH3)3−C
2. (CH3)2−CH (D) CH3−CH2
3. E D<C<C<B<A
4. E D<C<C<A<B

Correct answer: E D<C<C<A<B

Solution

The stability of alkyl radicals increases with the number of alkyl groups attached to the carbon bearing the unpaired electron due to hyperconjugation and inductive effects. Thus, the order is CH3−CH2 < (CH3)2−CH < (CH3)3−C < (CH3)2C−CH2CH3.

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