StreakPeaked· Practice

ExamsNEETChemistry

AgBr has the highest solubility in 10^-3 M NH4OH. AgBr is less soluble in NaBr and HBr due to presence of common ion (Br). With NH4OH, AgBr will react as: AgBr(s) + 2NH4OH(aq.) → [Ag(NH3)2]Br(aq.) + 2H2O(l) Hence, the highest solubility with NH4OH solution.

  1. AgBr has the highest solubility in 10^-3 M NH4OH.
  2. AgBr is less soluble in NaBr and HBr due to presence of common ion (Br).
  3. AgBr(s) + 2NH4OH(aq.) → [Ag(NH3)2]Br(aq.) + 2H2O(l)
  4. Hence, the highest solubility with NH4OH solution.

Correct answer: AgBr has the highest solubility in 10^-3 M NH4OH.

Solution

The solubility of AgBr is highest in NH4OH due to the formation of the complex ion [Ag(NH3)2]+, which reduces the concentration of free Ag+ ions, driving the dissolution equilibrium forward.

Related NEET Chemistry questions

⚔️ Practice NEET Chemistry free + battle 1v1 →