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B4A → B + 2A (s) Solubility product = [s] [2s]^2 = 4s^3 4 × 10^-12 = 4s^3 or s = (4 × 10^-12 / 4)^(1/3)

1. 4 × 10^-12 = 4s^3
2. s = 10^-4
3. Solubility product = [s] [2s]^2 = 4s^3
4. s = (4 × 10^-12 / 4)^(1/3)

Correct answer: s = 10^-4

Solution

The solubility (s) is calculated as s = (4 × 10^-12 / 4)^(1/3), which simplifies to s = 10^-4. This matches option B.

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