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Ag₂C₂O₄ ⇌ 2Ag⁺ (aq) + C₂O₄²⁻ (aq). Ksp = [Ag⁺]²[C₂O₄²⁻]. [Ag⁺] = 2.2 × 10⁻⁴ M.

1. Concentration of C₂O₄²⁻ ions, [C₂O₄²⁻] = 2.2 × 10⁻⁴ / 2 = 1.1 × 10⁻⁴ M
2. Concentration of C₂O₄²⁻ ions, [C₂O₄²⁻] = 2.2 × 10⁻⁴ / 2 = 1.1 × 10⁻³ M
3. Concentration of C₂O₄²⁻ ions, [C₂O₄²⁻] = 2.2 × 10⁻⁴ / 2 = 1.1 × 10⁻² M
4. Concentration of C₂O₄²⁻ ions, [C₂O₄²⁻] = 2.2 × 10⁻⁴ / 2 = 1.1 × 10⁻¹ M

Correct answer: Concentration of C₂O₄²⁻ ions, [C₂O₄²⁻] = 2.2 × 10⁻⁴ / 2 = 1.1 × 10⁻⁴ M

Solution

The dissociation of Ag₂C₂O₄ produces 2 moles of Ag⁺ for every 1 mole of C₂O₄²⁻. Given [Ag⁺] = 2.2 × 10⁻⁴ M, the concentration of C₂O₄²⁻ is half of [Ag⁺], i.e., 1.1 × 10⁻⁴ M.

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