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Ca(OH)₂ ⇌ Ca²⁺ + 2OH⁻. pH = 9, pOH = 14 - 9 = 5. [OH⁻] = 10⁻⁵.

1. Ksp = [Ca²⁺][OH⁻]² = (10⁻⁵/2) × (10⁻⁵)²
2. Ksp = [Ca²⁺][OH⁻]² = (10⁻⁵) × (10⁻⁵)²
3. Ksp = [Ca²⁺][OH⁻]² = (10⁻⁵/2) × (10⁻⁵)
4. Ksp = [Ca²⁺][OH⁻]² = (10⁻⁵) × (10⁻⁵)

Correct answer: Ksp = [Ca²⁺][OH⁻]² = (10⁻⁵/2) × (10⁻⁵)²

Solution

The dissociation of Ca(OH)₂ gives 1 mole of Ca²⁺ for every 2 moles of OH⁻. Since [OH⁻] = 10⁻⁵, [Ca²⁺] = 10⁻⁵/2. Substituting these values into Ksp = [Ca²⁺][OH⁻]² gives Ksp = (10⁻⁵/2) × (10⁻⁵)².

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