Exams › NEET › Chemistry

CaF₂ ⇌ Ca²⁺ + 2F⁻. Due to common ion effect of NaF, solubility of CaF₂ is further suppressed. Therefore, the concentration of F⁻ will be mainly due to NaF.

1. Ksp = [Ca²⁺][F⁻]²
2. Ksp = [Ca²⁺][F⁻]
3. Ksp = [Ca²⁺][F⁻]³
4. Ksp = [Ca²⁺][F⁻]⁴

Correct answer: Ksp = [Ca²⁺][F⁻]²

Solution

The solubility product (Ksp) for CaF₂ is defined as the product of the concentrations of its dissociated ions, with the stoichiometric coefficients as exponents. Since CaF₂ dissociates into one Ca²⁺ and two F⁻ ions, Ksp = [Ca²⁺][F⁻]².

Related NEET Chemistry questions

• A beaker contains a saturated solution of copper(l) chloride. Copper(l) chloride is slightly soluble salt with a solubility product of \( 1.2 \times 10^{-6} \) Which of the following salts when added to the solution would precipitate copper(l) chloride?
• The function of 'buffer solution' is:
• When \( C a(O H)_{2} \) attains solubility equilibrium, the:
• Predict if there will be any precipitate by mixing \( 50 \mathrm{mL} \) of \( 0.01 \mathrm{M} \) NaCl and 50 mL of \( 0.01 \mathrm{M} A g N O_{3} \) solution. The solubility product of \( A g C l \) is \( 1.5 \times \) \( 10^{-10} \)
• Calculate the ratio of \( H C O O^{-} \) and \( F^{-} \) in a mixture of \( 0.2 M \) HCOOH \( \left(K_{a}=\right. \) \( \left.2 \times 10^{-4}\right) \) and \( 0.1 M H F\left(K_{a}=6.6 \times\right. \) \( \left.10^{-4}\right) \)
• What is the [OH⁻] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)₂?

⚔️ Practice NEET Chemistry free + battle 1v1 →