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Given, CH3COOH ⇌ CH3COO⁻ + H⁺; Ka = 1.5 × 10⁻⁵.

1. Ka = 1.5 × 10⁻⁵
2. Ka = 1.5 × 10⁻⁴
3. Ka = 1.5 × 10⁻³
4. Ka = 1.5 × 10⁻²

Correct answer: Ka = 1.5 × 10⁻⁵

Solution

The given equilibrium constant (Ka) for acetic acid is explicitly stated as 1.5 × 10⁻⁵ in the question, making option A correct.

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