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In exothermic reactions on increasing temperature value of Kp decreases.

1. Kp > Kp' (Assuming T₁ < T₂)
2. Kp < Kp' (Assuming T₁ > T₂)
3. Kp = Kp' (Assuming T₁ = T₂)
4. Kp ≠ Kp' (Assuming T₁ ≠ T₂)

Correct answer: Kp > Kp' (Assuming T₁ < T₂)

Solution

For exothermic reactions, increasing temperature shifts the equilibrium towards the reactants, decreasing Kp. Thus, at a higher temperature (T₂), Kp' is smaller than Kp at a lower temperature (T₁).

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