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For the reaction XeF6(g) + H2O(g) ⇌ XeOF4(g) + 2HF(g), K1 = [XeOF4][HF]² / [XeF6][H2O]. For the reaction XeO(g) + XeF6(g) ⇌ XeOF4(g) + H2O(g) + HeO2F2(g), K2 = [XeO4][XeF6] / [XeO4][XeF6].

1. K1 = [XeOF4][HF]² / [XeF6][H2O]
2. K2 = [XeO4][XeF6] / [XeO4][XeF6]
3. K = K1 × K2
4. K = K1 / K2

Correct answer: K = K1 / K2

Solution

The equilibrium constant for the overall reaction is derived by dividing K1 by K2, as the second reaction reverses part of the first reaction. This results in K = K1 / K2.

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