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For the reaction 2A(g) + B(g) ⇌ 3C(g) + D(g), mole ratio is given as 2:1:3:1. Molar concentration at equilibrium is given as [A] = 0.50, [B] = 0.75, [C] = 0.75, [D] = 0.25. Calculate Kc.

1. [C]^3[D] / [A]^2[B]
2. (0.75)^3(0.25) / (0.50)^2(0.75)
3. 0.75
4. 0.25

Correct answer: (0.75)^3(0.25) / (0.50)^2(0.75)

Solution

The equilibrium constant expression for the reaction is Kc = [C]^3[D] / [A]^2[B]. Substituting the given equilibrium concentrations into this expression, we get Kc = (0.75)^3(0.25) / (0.50)^2(0.75), which matches option B.

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