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For the reaction 2SO2 + O2 ⇌ 2SO3, K = 278 (given). Calculate K' for the reaction SO3 ⇌ SO2 + 1/2 O2.

1. 1 / √278
2. 6 × 10^-2
3. √278
4. 1 / K

Correct answer: 1 / √278

Solution

The given reaction is the reverse of the original reaction with its stoichiometry halved. For a reversed reaction, K' = 1/K, and halving the stoichiometry changes K' to √(1/K). Thus, K' = 1/√278.

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