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Solubility of MX2-type electrolytes is 0.5 × 10⁻⁴ mol/lit, then find out Ksp of electrolytes.

1. 5 × 10⁻¹²
2. 25 × 10⁻¹⁰
3. 1 × 10⁻¹³
4. 5 × 10⁻¹³

Correct answer: 5 × 10⁻¹³

Solution

For an MX2 electrolyte, the dissociation is MX2 → M²⁺ + 2X⁻. If solubility is s = 0.5 × 10⁻⁴ mol/L, then [M²⁺] = s and [X⁻] = 2s. Ksp = [M²⁺][X⁻]² = (s)(2s)² = 4s³ = 4 × (0.5 × 10⁻⁴)³ = 5 × 10⁻¹³.

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