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The solubility product of AgI at 25°C is 1.0 × 10⁻¹⁶ mol² L⁻². The solubility of AgI in 10⁻⁴ N solution of KI at 25°C is approximately (in mol L⁻¹)

1. 1.0 × 10⁻⁸
2. 1.0 × 10⁻¹⁶
3. 1.0 × 10⁻¹²
4. 1.0 × 10⁻¹⁰

Correct answer: 1.0 × 10⁻⁸

Solution

The solubility of AgI in the presence of KI is reduced due to the common ion effect. Using the solubility product (Ksp = [Ag⁺][I⁻]) and assuming [I⁻] ≈ 10⁻⁴ M from KI, the solubility of AgI is calculated as Ksp/[I⁻] = (1.0 × 10⁻¹⁶)/(10⁻⁴) = 1.0 × 10⁻⁸ mol L⁻¹.

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