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ExamsNEETChemistry

The solubility product of a sparingly soluble salt AX2 is 3.2 × 10⁻¹¹. Its solubility (in moles/litre) is

  1. 5.6 × 10⁻⁶
  2. 3.1 × 10⁻⁴
  3. 2 × 10⁻⁴
  4. 4 × 10⁻⁴

Correct answer: 5.6 × 10⁻⁶

Solution

For a salt AX2, the solubility product (Ksp) is given by Ksp = 4s³, where s is the solubility. Solving 3.2 × 10⁻¹¹ = 4s³ gives s = 5.6 × 10⁻⁶ mol/L.

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