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If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is:

1. 4.00 × 10⁻³ M³
2. 4.00 × 10⁻⁷ M³
3. 5.00 × 10⁻⁶ M³
4. 5.00 × 10⁻¹² M³

Correct answer: 4.00 × 10⁻⁷ M³

Solution

The pH of 12 implies a pOH of 2, so [OH⁻] = 10⁻² M. For Ba(OH)₂, [Ba²⁺] = 0.5[OH⁻] = 0.5 × 10⁻² M. Ksp = [Ba²⁺][OH⁻]² = (0.5 × 10⁻²)(10⁻²)² = 4.00 × 10⁻⁷ M³.

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