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Ionisation constant of CH3COOH is 1.7 × 10⁻⁵. If concentration of H⁺ ions is 3.4 × 10⁻⁴ M, then find out initial concentration of CH3COOH molecules.

1. 3.4 × 10⁻⁴ M
2. 3.4 × 10⁻³ M
3. 6.8 × 10⁻³ M
4. 6.8 × 10⁻⁴ M

Correct answer: 6.8 × 10⁻³ M

Solution

The ionization constant (Ka) is given by Ka = [H⁺]² / [CH3COOH_initial]. Rearranging, [CH3COOH_initial] = [H⁺]² / Ka = (3.4 × 10⁻⁴)² / (1.7 × 10⁻⁵) = 6.8 × 10⁻³ M.

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