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In H₃S⁻, I⁻, RNH₂, and NH₃, order of proton accepting tendency will be:

1. I⁻ > NH₃ > RNH₂ > H₃S⁻
2. H₃S⁻ > RNH₂ > NH₃ > I⁻
3. RNH₂ > NH₃ > H₃S⁻ > I⁻
4. NH₃ > RNH₂ > H₃S⁻ > I⁻

Correct answer: RNH₂ > NH₃ > H₃S⁻ > I⁻

Solution

Proton accepting tendency depends on basicity. Amines (RNH₂) are more basic than ammonia (NH₃) due to the +I effect of the alkyl group. H₃S⁻ is less basic than amines and ammonia, and I⁻ is the least basic due to its large size and low charge density.

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