Correct answer: 12.65
When equal volumes of NaOH and HCl are mixed, the moles of each are calculated. NaOH has 0.1 M × V moles, and HCl has 0.01 M × V moles. The excess OH⁻ concentration is (0.1 - 0.01) M = 0.09 M. The pOH is -log(0.09), and pH = 14 - pOH ≈ 12.65.