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Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:

1. 60 mL M/10 HCl + 40 mL M/10 NaOH
2. 55 mL M/10 HCl + 45 mL M/10 NaOH
3. 75 mL M/5 HCl + 25 mL M/5 NaOH
4. 100 mL M/10 HCl + 100 mL M/10 NaOH

Correct answer: 60 mL M/10 HCl + 40 mL M/10 NaOH

Solution

In option A, the moles of HCl (acid) exceed the moles of NaOH (base), resulting in an acidic solution. The other options either result in neutral or basic solutions.

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