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For a given exothermic reaction, Kp and Kp' are the equilibrium constants at temperatures T₁ and T₂ respectively. Assuming that heat of reaction is constant in temperature range between T₁ and T₂, it is readily observed that:

1. Kp > Kp'
2. Kp < Kp'
3. Kp = Kp'
4. Kp = 1/Kp'

Correct answer: Kp > Kp'

Solution

For an exothermic reaction, increasing temperature decreases the equilibrium constant (Kp) because the reaction shifts in the reverse direction to counteract the added heat. Thus, Kp > Kp' when T₁ < T₂.

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