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Hydrolysis of sucrose is given by the following reaction: Sucrose + H₂O ⇌ Glucose + Fructose. If the equilibrium constant (Kc) is 2 × 10¹³ at 300 K, the value of ΔG° at the same temperature will be:
- 8.314 J mol⁻¹ K⁻¹ × 300 K × ln(2 × 10¹³)
- 8.314 J mol⁻¹ K⁻¹ × 300 K × ln(3 × 10¹³)
- -8.314 J mol⁻¹ K⁻¹ × 300 K × ln(4 × 10¹³)
- -8.314 J mol⁻¹ K⁻¹ × 300 K × ln(2 × 10¹³)
Correct answer: -8.314 J mol⁻¹ K⁻¹ × 300 K × ln(2 × 10¹³)
Solution
The relationship between ΔG° and Kc is given by ΔG° = -RT ln(Kc). Substituting R = 8.314 J mol⁻¹ K⁻¹, T = 300 K, and Kc = 2 × 10¹³, the correct expression is -8.314 × 300 × ln(2 × 10¹³).
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