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The rate constant for forward and backward reaction of hydrolysis of ester are 1.1×10⁻² and 1.5×10⁻³ per minute respectively. Equilibrium constant for the reaction CH₃COOC₂H₅ + H⁺ ⇌ CH₃COOH + C₂H₅OH is:
- 4.33
- 5.33
- 6.33
- 7.33
Correct answer: 4.33
Solution
The equilibrium constant (K) is the ratio of the rate constant of the forward reaction (k₁) to the rate constant of the backward reaction (k₋₁). Here, K = k₁ / k₋₁ = (1.1×10⁻²) / (1.5×10⁻³) = 4.33.
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