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If K1 and K2 are the respective equilibrium constants for the two reactions XeOF4(g) + H2O(g) ⇌ XeO2F2(g) + 2HF(g) XeO4(g) + XeF6(g) ⇌ XeOF4(g) + XeO2F2(g) The equilibrium constant of the reaction XeO4(g) + 2HF(g) ⇌ XeO3F2(g) + H2O(g) will be:

1. K1 / (K2)²
2. K1 · K2
3. K1 / K2
4. K2 / K1

Correct answer: K1 / K2

Solution

The given reaction can be derived by combining and rearranging the two provided reactions. The equilibrium constant for the resulting reaction is obtained by dividing K1 by K2, as the second reaction is reversed and its equilibrium constant becomes 1/K2.

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